Periyodik Sistemin ve Depremlerin Matematiksel Analizi

(Timur İlikanempIDB) #1

+ =


(Z)(W)+(Z)(Ge)-Periyotno(w)=74+32-6= 100 =(Z)(Fm)
(A)(W)+(A)(Ge)=184+73= 257 =(A)(Fm)

+ =


(Z)(W)+(Z)(Ge)=74+32= 106 =(Z)(Sg)
(A)(W)+(A)(Ge)+Grup no(Ge)-Periyotno(Ge)-Periyotno(Sg)+Grup
no(Sg)=184+73+14-4-7+6= 266 =(A)(Sg)

+ =


(Z)(W)+(Z)(Br)=74+35= 109 =(Z)(Mt)
(A)(W)+(A)(Br)+Periyotno(Br)=184+80+4= 268 =(A)(Mt)

+ =


(Z)(W)+(Z)(Sr)-Periyotno(Rg)+Periyotno(W)=74+38-7+6= 111 =(Z)(Rg)
(A)(W)+(A)(Sr)=184+88= 272 =(A)(Rg)


+ =


(Z)(W)+(Z)(Sr)=74+38= 112 =(Z)(Cn)
(A)(W)+(A)(Sr)+Periyotno(Sr)=184+88+5= 277 =(A)(Cn)

+ =


(Z)(W)+(Z)(Nb)-Periyotno(Hs)=74+41-7= 108 =(Z)(Hs)
(A)(W)+(A)(Nb)=184+93= 277 =(A)(Hs)

+ =


(Z)(W)+(Z)(Nb)=74+41= 115 =(Z)(Mc)
(A)(W)+(A)(Nb)+Periyotno(W)+Periyot
no(Hs)=184+93+6+7= 290 =(A)(Mc)
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