Periyodik Sistemin ve Depremlerin Matematiksel Analizi

(Timur İlikanempIDB) #1

4)Grup no(Ge)/Periyotno(Cn)+Grup no(Hg)/Grup
no(Cn)+(A)(Hg)+(A)(Ge)=14/7+12/12+201+73= 277 =(A)(Cn)
5)(Periyotno(Ge)+Grup no(Ge))/Periyot
no(Hg)+(A)(Hg)+(A)(Ge)=(4+14)/6+201+73= 277 =(A)(Cn)
6)Periyotno(Cn)-Periyotno(Ge)+(A)(Hg)+(A)(Ge)=7-
4+201+73= 277 =(A)(Cn)
7)Periyotno(Hg)/(Grup no(Ge)-Grup no(Hg))+(A)(Hg)+(A)(Ge)=6/(14-
12)+201+73= 277 =(A)(Cn)


+ =


(Z)(Hg)+(Z)(Br)-Grup no(Br)+Grup no(Hg)=80+35-17+12= 110 =(Z)(Ds)
(A)(Hg)+(A)(Br)=201+80= 281 =(A)(Ds)

+ =


(Z)(Hg)+(Z)(Br)=80+35= 115 =(Z)(Mc)
(A)(Hg)+(A)(Br)+Grup no(Br)-Grup no(Hg)+Periyotno(Br)=201+80+17-
12+4= 290 =(A)(Mc)

+ =


(Z)(Hg)+(Z)(Sr)-(Grup no(Fl)/Periyotno(Fl))-Grup no(Sr)=80+38-
(14/7)-2= 114 =(Z)(Fl)
(A)(Hg)+(A)(Sr)=201+88= 289 =(A)(Fl)

+ =


(Z)(Hg)+(Z)(Sr)=80+38= 118 =(Z)(Og)
(A)(Hg)+(A)(Sr)+Periyotno(Sr)=201+88+5= 294 =(A)(Og)

(a 28 )=(3*28)-1= 83’tür. Buna göre:


+ =


(Z)(Bi)+(Z)(He)=83+2= 85 =(Z)(At)
1)(A)(Bi)+(A)(He)-Grup no(He)/Periyotno(At)=209+4-18/6= 210 =
(A)(At)
2)(A)(Bi)+(A)(He)- Grup no(Bi)/(Periyotno(Bi)-Periyot
no(He))=209+4-15/(6-1)= 210 =(A)(At)

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