Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1
Finding the Common Ratio

Determine the common ratio rfor the geometric sequence.


To find r, choose any two successive terms and divide the second one by the first.


We choose the second and third terms of the sequence.


Substitute.

Write as division.

Definition of division

Multiply. Write in lowest terms.

Any other two successive terms could have been used to find r. Additional terms of the


sequence can be found by multiplying each successive term by NOW TRY


OBJECTIVE 2 Find the general term of a geometric sequence. The general


term of a geometric sequence is expressed in terms of and rby


writing the first few terms as


which suggests the next rule.


a 1 , a 2 = a 1 r, a 3 =a 1 r^2 , a 4 = a 1 r^3 ,Á,


an a 1 , a 2 , a 3 ,Á a 1


1

2.


=


1


2


=


15


4


#^2


15


=


15


4


,


15


2


=


15
4
15
2

r=


a 3


a 2


15,


15


2


,


15


4


,


15


8



EXAMPLE 1


692 CHAPTER 12 Sequences and Series


NOW TRY
EXERCISE 1
Determine rfor the geometric
sequence.


1
4

, -1, 4, -16, 64,Á


NOW TRY ANSWERS





    • 4




General Term of a Geometric Sequence

The general term of the geometric sequence with first term and common


ratio ris


ana 1 rn^1.


a 1


CAUTION In finding be careful to use the correct order of operations.


The value of rn-^1 must be found first. Then multiply the result by a 1.


a 1 rn-^1 ,


Finding the General Term of a Geometric Sequence

Determine the general term of the sequence in Example 1.


The first term is and the common ratio is


Substitute into the formula for

It is not possible to simplify further, because the exponent must be applied before the


multiplication can be done. NOW TRY


an= a 1 rn-^1 = 15 a an.


1


2


b


n- 1

r=


1

a 1 = 15 2.


NOW TRY EXAMPLE 2


EXERCISE 2
Determine the general term of
the sequence.


1
4

, -1, 4, -16, 64,Á



  1. an=^14 1 - 42 n-^1

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