Intermediate Algebra (11th edition)

(Marvins-Underground-K-12) #1






















41.By the vertical line test the set is not a function, because a vertical


line may intersect the graph of an ellipse in two points.



  1. ,









    1. (a)10 m (b)36 m



  2. (a)154.7 million mi (b)128.7 million mi (Answers are rounded.)



    1. ;




Section 11.3 (pages 655–657)


1.C 3.D












  1. 13.hyperbola 15.ellipse


17.circle 19.parabola 21.hyperbola


1 3, 0 21 0, 4 2

323 units

y 1 = 4 + 216 - 1 x+ 222 y 2 = 4 - 216 - 1 x+ 222

Section 11.4 (pages 662–663)


1.one 3.none





































27.
















  1. 51 i, 2i 2 , 1 - i, - 2 i 2 , 1 2, - 12 , 1 - 2, 1 26


A 2 i 22 , 2 23 BF EA- 25 , - 25 B, A 25 , 25 BF

EA-^2 i^22 , -^223 B,A-^2 i^22 , 2^23 B,A^2 i^22 , -^223 B,

EA- 223 , - 2 B, A- 223 , 2B,A 223 , - 2 B, A 223 , 2BF

51 - 2, 0 2 , 1 2, 0 (^26) EA 23 , 0B, A- 23 , 0BF
a-
23
3
i, -
1
2



  • 23
    6
    ea ibf
    23
    3
    i, -
    1
    2



  • 23
    6
    ib,


EA-^23 , 0B, A^23 , 0B,A-^25 , 2B, A^25 , 2BF

51 - 3, 1 2 , 1 1, - 326 EA-^32 , - 49 B, 1 - 2, 0 2 F

EA- 51 , 57 B,^1 1, -^12 F E^1 - 2, -^22 , A-^43 , -^3 BF

E 1 0, 0 2 , A 21 , 21 BF 51 - 6, 9 2 , 1 - 1, 4 26

A-28 Answers to Selected Exercises


x

y

0 3

5

x^2
9

y^2
+= 1 25

x

y

(^06)
4
x^2
36
y^2
+= 1 16
x
y
0 4
x^2
16
y^2



  • 4 = 1
    2
    x
    y
    0
    5
    7
    y^2
    25
    x^2
    = 1 – 49
    x
    y
    (–1, 2)
    0
    2
    9
    7
    (x + 1)^2
    64
    (y – 2)^2
    += 1 49
    x
    y
    0
    –2–2^26
    (x – 2)^2
    16
    (y – 1)^2

  • 9 = 1
    (2, 1)
    10
    –10



  • 15 15


10

–10

–15 15

x

y

–4 24

4
(–3, 4) 2 (3, 4)

(–3, –4) (3, –4)

–2

x

y

0
4

3

x^2
16

y^2
–= 1 9

x

y

05

2

y^2
4

x^2
–= 1 25

x

y

05

6

x^2
25

y^2
–= 1 36

x

y

0

4

–4

–4 4

y^2
16

x^2
–= 1 16

x

y

0

4
4

x^2 – y^2 = 16

x

y

0 2

4

4 x^2 + y^2 = 16

x

y

06
y^2 = 36 – x^2

x

y

02

4

x^2 – 2y = 0

x

y

02

2

y^2 = 4 + x^2

x

y

0

2
–4 4
f(x) = √16 – x^2

23.domain: ;
range: 3 0, 4 4

3 - 4, 4 4 25.domain: ;
range: 3 - 6, 0 4

3 - 6, 6 4 27.domain: ;
range: 3 - 2, 0 4

3 - 3, 3 4

x

y

0

–6

–6

6

f(x) = –√36 – x^2
x

y

0

–3
–2

3
9
y = –2 1 –x^2

29.domain: ;
range: 3 3, q 2

1 - q, q 2

x

y

0

3
3

y
3

x^2
= √1 + 9









x

y

0

2
–1
(2, –1)

(x – 2)^2
4

(y + 1)^2
–= 1 9

x

y

02

y^2
36

(x – 2)^2
–= 1 49

(2, 0)


  1. (a)50 m (b)69.3 m 37. ,









    1. 47.e 23 , 
      22
      2
      51 2, 9 26 51 - 1, 2 26 if




y 2 =-
B

x^2
9
y 1 = - 1
B

x^2
9


  • 1


10

–10

–15 15

10

–10

–15 15

y

0 x

y

0 x
0 x

y

x

y

0
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