(d) Breast line requirements, using formula (27):
BR x MBL = 7734 + 2272 = 10006 kN
Assuming that the ship has a total of 10 breast lines (BR = 10) symmetrically arranged
(five forward and five aft), the minimum breakiog slrength required for each line will be:
10006
MBL = -- = 1000 kN (= 102 tonnes force)
)0
For a 125,OOOmJ gas carrier (spherical tanks)
(a) Ship particulars:
LDP = 274.0 m
D = 25.0 m
T = 9.0 m (average ballast draft)
AT = 1382 m^2 (al average ballast draft)
A L = 7122 m^2 (al average baUast draft)
(b) Maximum forces on the ship, by use of formulae (19), (20) and (21):
F, max = 825 + 105 = 930 kN
Fy,' max = 2457 + 572 = 3029 kN
F~Amax = 2600 + 612 = 32J2 kN
(c) Spring line requirements, by use of formula (28):
S )( MBL = 3300 + 419 = 3719 kN
Assuming the ship has a total of four spring lines (S = 4); the minimum breaking strength
required for eacb line will be:
3719
MBL = --= 930 kN (= 95 connes force)
4
(d) Breast line requirements, using formula (29):
BR )( MBL = 13518 + 3184 = 16702 kN
Assuming that the ship has a total of 14 breast lines (B = t4) symmetrically arranged
(seven forward and seven aft), the minimum breaking strength required for each wire
wiU be:
MBL =
16702
14
= 1193 kN (= 12210nnes force)