- MODEL GEOMETRIES 5
on TxMn, one obtains a Yx-invariant scalar product gx by averaging §x un-
der the action of Yx ".::=: g*. Then since g is transitive, there exists for any
y E Mn an element 'Yyx E g such that 'Yyx (y) = x. So one may define a
scalar product gy for all V, W E TyMn by
gy (V, W) ~ b;xgx) (V, W) = gx (hyxt V, ('Yyxt W).
To see that gy is well defined, suppose that 'Y~x is another element of g such
that "f~x (y) = x. Then "f~x o "f;} E Yx, so by Yx-invariance of gx, we have
('Y;xgx) (V, W) = gx ( ('Y~x^0 'Y;x^1 )J'Yyx) V, ('Y~x o 'Y;x^1 )J'Yyx) w)
= gx ( b~xL V, b~xL w) = (b~xr gx) (V, W).
Because the action of g is smooth, one obtains in this way a smooth Rie-
mannian metric g on Mn. Because the action of g is transitive, g is complete
by Proposition 1.8. D
To complete the connection between homogeneous models and model
geometries, we want to establish the converse of the construction above.
Namely, we want to show that every homogeneous model (Mn,g) may be
regarded as a model geometry (Mn, 9, 9*). We begin by recalling some
classical facts about the set Isom (Mn, g) of isometries of a Riemannian
manifold. Isom (Mn, g) is clearly a subgroup of the diffeomorphism group
'.D (Mn). Moreover, it is clear that (Mn, g) is homogeneous if and only if
Isom (Mn, g) acts transitively on Mn. The following facts are classical. (See
[100] and [87].)
PROPOSITION 1.10. Let (Mn, g) be a smooth Riemannian man4old.
( 1) Isom (Mn, g) is a Lie group and acts smoothly on Mn.
(2) For each x E Mn, the isotropy group
Ix (Mn,g) ~ b E Isom (Mn,g): "( (x) = x}
is a compact subgroup ofisom(Mn,g).
(3) For each x E Mn, the linear isotropy representation
defined by
Ax ( "() = "(* : TxMn --* TxMn
is an injective group homomorphism onto a closed subgroup of the
orthogonal group 0 (TxMn, g ( x)). In particular,
Ix (Mn, g) ".::=:Ax (Ix (Mn, g)) ~ 0 (TxMn, g (x))
is compact.