(^244) 23. HEAT KERNEL FOR STATIC METRICS
since t - s is bounded from above. However, from this estimate (contrast
with (23.88)) we cannot conclude that the integral
(23.95)
1
t1 {) EPPN.
8
. (x,z,t-s)G(z,y,s)dμ(z)ds
o M xi xJ
converges absolutely.
The idea for solving this issue is to integrate by parts, i.e., to use the
divergence theorem. To accomplish this, we first need to 'move' the par-
tial derivatives from the x variable onto the z variable. Recall that we
are assuming (U, {xi} ~= 1 ) are geodesic coordinates centered at x E U and
B (x, inj (g)) CU; in particular,
supp (PN (x, ·, s)) CU.
Let
[)2pN [)2 PN
.. (x, z, ·) = {).
8
[)xi {)xJ xi xJ. (x, z, ·)
x x
denote the original second partial derivatives with respect to the x variable
in the coordinates {xi} and let
82 PN.
-~-i-. {)--;-j ( x' z'. )
UXz Xz
denote the second partial derivative with respect to the z variable in the
same coordinates {xi} centered at x, which is well defined since z EU.
Since supp (PN (x, ·, s)) c U, we may write the expression in (23.94) as
1 (
{)^2 PN {)^2 PN )
.. - .. (x,z,t-s)G(z,y,s)dμ(z)
M [)xi x {)xJ x [)xi z 8xJ z
(23.96)
1
[)2pN
+.. (x, z, t - s) G (z, y, s) dμ (z).
M [)xi[)xJ z z
(I) We shall estimate the first term in (23.96) to show that the integral
1
t 1 ( [)2. PN j - [)2 .. PN ) (x,z,t-s)G(z,y,s)dμ(z)ds
.^0 M [)xi x 8x x [)xi z 8xJ z ·
(23.97)
converges absolutely.
(I-1) First and second derivatives of the distance function. Observe that
for (x, z) E Minj(g) such that x #-z
{) {)
(23.98) -
8
. d (x, z) + -
8
. d (x, z) = 0.
xi£ x~
Indeed, using d^2 (x, z) = ~J=l xJ (z)^2 , first we compute
{) 2.. {) (~. 2) i
{)xt d (x, z) = {)xt f:;;. xJ (z) = 2x (z),