130 29. COMPACT 2-DIMENSIONAL ANCIENT SOLUTIONS
The proof of this lemma shall occupy the rest of this section. The totally
symmetric and trace-free 3-tensor a, defined by (29.171) in Euclidean coordinates,
is given invariantly by a= \7^3 v-~ S(6euc 'Vv®geuc), where \7 denotes the Euclidean
covariant derivative. Let (r , B) be polar coordinates. By (29.175), now using the
orthonormal frame 8 ~ 1 = gr and 8 ~ 2 = ~ %e, we have on ffi.^2 that
where
et=;= -. n3 VrrrV--^3 r -2n3 veerV->
(3-:::;=. r - 3 nveeeV^3 - -^3 r -ln2 vrrev. -
Next, we express a and /3 in terms of the partial derivatives of v with respect
to r and (}. We have I'~e = I'~r = ~ and f&e = -r and the rest of the Euclidean
Christoffel symbols are zero. Therefore the components of the Hessian of v are
given by
n2 v rrV - = Vrr, -
'V~ev = Vee + rvri
1
v;ev = Ver - -ve.
r
Taking another covariant derivative, we have
Therefore,
n3 v rrrV - == Vrrr, -
'V~eev = veee + 3rvre - 2ve,
2
'V~erv = Vree - -Vee+ rvrr - Vr,
r
2 2
v:rev = Verr - -Ver + 2Ve.
r r
a= Vrrr - 3r-^2 vree + 6r-^3 vee - 3r-^1 vrr + 3r-^2 vr ,
/3 = r-^3 veee - 3r-^1 verr + 9r-^2 vre - 8r-^3 ve.
To express Q o u-^1 in terms of the partial derivatives of v with respect tor and
e, we first express Q in terms of the partial derivatives of v with respect to 'lj; and
B. Since 8 ~1 = f..p and 8 ~2 = sec 'lj; %e are orthonormal with respect to g 5 2, from
(29.163) and (29.169), we have on S^2 that
Q = v ITF(B)l
2
= ~ (a^2 + (3^2 ),
where
a~ \7~..p..p v - 3 sec^2 'lj;'V~eev - 2\7..pv,
f3 ~ sec^3 'l/;'V~eev - 3 sec 'lj;\7~..p..pv - 2 sec 'lj;\7 ev.