Heat conduction equation with constant coefficients 309
and the harmonic in question is stable. Under the choice I qk I < 1, we have
II Y(k) II < II Y(k) II When this is the case, the scheme is said to be stable
in every harmonic.
We now assign the values of(} such that either I qk I < 1 or -1 <
qk < 1, which guarantees the stability of the scheme in every harmonic.
It is clear from the formula qk = 1-TAk(l + (}TAk)-^1 that qk < 1 if
1 + (} T Ak > 0, that is,(}> -(r >-d-^1. The bound qk > -1 or
1
2+(2()-l)r>-k
qk + = l+(}TAk -> 0
is ensured by the restriction 2+ (2()-l)rAk > 0 or(}>~ -(r>-k)-^1 • In
that case the condition 1 + (}T Ak > 0 is automatically fulfilled. Since
4
Ak < AN-1 < h2
the following relations occur:
1
--- <
TAk -
h2
4r
Hence, the condition I qk I < 1 holds true for all k = l, 2, ... , N - 1 under
the agreement that
(23)
1
(} > -
2
h2
4r
Thus, all of the hannonics Y(k) = Tk X (k) are stable under one and the
same con di ti on (} > (} 0. We are going to show that the stability of scheme
(16a) in every harmonic known as the spectral stability implies that in the
grid L 2 -norm with respect to the initial data y(x, 0) = u 0 (x), where u 0 (x)
is a grid function defined for 0 < x < 1 and vanishing at the points x = 0
and x = 1. \tVith this aim, the general solution of problem (16a) is sought
as the sum of particular solutions having the form (22):
N-l
1111112 = 2= if,
k=!
Substituting here Tk = qk Tk and taking into account (20), we find
that
N-1
y= L qkTk ~X(k),
k=l