1549312215-Complex_Analysis_for_Mathematics_and_Engineering_5th_edition__Mathews

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1.2 • THE ALGEBRA OF COMPLEX NUMBERS 15

(i) Re [(x + iy) (x -iy)J.
{j) Im [(x + iy)^3 ].


  1. Show tha.t zz is always a. real number.

  2. Verify Identities ( 1-1 2 )-(1-19).

  3. Let P (z) = a,.z" + a,,_,z"-^1 +···+a, z + ao be a. polynomial of degree n.


(a) Suppose that a,,, an- 1, ... , a 1, ao a.re all real. Show that if z1 i s a.root
of P , t hen Zi is also a root. In other words, the roots must be complex
conjugates, something you likely lea.med without proof in high school.
(b) Suppose not all of a,., a,,._,,. .. , a,, ao a.re rea.1. Show that P has a.t
least one root whose complex conjugate is not a root. Hint: Prove the
contrapositive.
(c) Find an example of a. polynomial that has some roots occurring as
complex conjugates, and some not.


  1. Let z 1 = (x 1 , yi) and z 2 = (x 2 , y 2 ) be arbitrary complex numbers. Prove or
    disprove the following.


(a) Re(z1 + z2) = Re(z1) + Re(z2).
(b) Re(z1z2) =Re (z1) Re (.zz).
(c) Im (z1 + z2) =Im (z1) +Im (z2).
(d) Im(z 1 z2) =Im (z1) Im (z2).


  1. Prove that the complex number (1, 0) (which we identify with the real number 1)
    is the multiplicative identity for complex numbers.

  2. Use mathematica.J induction to show that the binomial theorem is valid for complex
    numbers. In othe r words, show that if z and w are arbit rary complex numbers a.nd
    n is a. positive integer, then (z +wt = E " G)zkwn-k, where m = k!(:~k)!.
    k =O

  3. Let's use the symbol for a new type of multiplication of complex numbers defined
    by z 1
    Z2 = (x1x2, y1y2). This exercise shows why this is an unfortuna t e definition.


(a) Use the definition given in property (P7) and state what the multi-
plicative identity ( would have to be for this new multiplica tion.
(b) Show that if you use this new multiplication, nonzero complex numbers
of the form (0, a) have no inverse. That is, show that if z = (0, a),
t here is no complex number w with the property that z * w = (, where
( is the multiplicative identity you found in pa.rt (a).



  1. Explain why the complex number (0, 0) (which, you recall, we identify with the
    real number 0) has no multiplicative inverse.




  2. Prove property (P9), the distributive law for complex numbers.



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