Ideal gas 89
∑N
i=1
y^2 i=E. (3.5.11)
Eqn. (3.5.11) is the equation of a (3N−1)-dimensional spherical surface of radius
√
E.
Thus, the natural thing to do is transform to spherical coordinates; what we need,
however, is a set of spherical coordinates for a 3N-dimensional sphere. Recall that
ordinary spherical coordinates in three dimensions consist of one radial coordinate,r,
and two angular coordinates,θandφ, with a volume element given byr^2 drd^2 ω, where
d^2 ω= sinθdθdφis the solid angle element. In 3Ndimensions, spherical coordinates
consist of one radial coordinate and 3N−1 angular coordinates,θ 1 ,...,θ 3 N− 1 with a
volume element dNy=r^3 N−^1 drd^3 N−^1 ω. The radial coordinate is given simply by
r^2 =
∑N
i=1
y^2 i. (3.5.12)
After transforming to these coordinates, the partition functionbecomes
Ω(N,V,E) =
E 0 (2m)^3 N/^2 VN
N!h^3 N
∫
d^3 N−^1 ω
∫∞
0
dr r^3 N−^1 δ
(
r^2 −E
)
. (3.5.13)
The solid angle element dnωis sinn−^1 θ 1 sinn−^2 θ 2 ···sinθn− 1 dθ 1 ···dθn, and the gen-
eral formula for the solid angle integral is
∫
dnω=
2 π(n+1)/^2
Γ
(n+1
2
), (3.5.14)
where Γ(x) is the Gamma function defined by
Γ(x) =
∫∞
0
dt tx−^1 e−t. (3.5.15)
According to eqn. (3.5.15), for any integern, we have
Γ(n) = (n−1)!
Γ
(
n+
1
2
)
=
(2n−1)!!
2 n
π^1 /^2. (3.5.16)
Finally, expanding theδ-function using eqn. (A.15), we obtain
Ω(N,V,E) =
E 0 (2m)^3 N/^2 VN
N!h^3 N
2 π^3 N/^2
Γ(3N/2)
×
∫∞
0
dr r^3 N−^1
1
2
√
E
[
δ(r−
√
E) +δ(r+
√
E)
]
. (3.5.17)
Because the integration range onris [0,∞), only the firstδ-function gives a nonzero
contribution, and, by eqn. (A.13), the result of the integration is