Phase space and partition function 141
The link between the macroscopic thermodynamic properties in eqn.(4.2.6) and
the microscopic states contained inQ(N,V,T) is provided through the relation
A(N,V,T) =−kTlnQ(N,V,T) =−
1
β
lnQ(N,V,β). (4.3.17)
In order to see that eqn. (4.3.17) provides the connection between the thermodynamic
state functionA(N,V,T) and the partition functionQ(N,V,T), we note thatA=
E−TSand thatS=−∂A/∂T, from which we obtain
A=E+T
∂A
∂T
. (4.3.18)
We also recognize thatE =〈H(x)〉, the ensemble average of the Hamiltonian. By
definition, this ensemble average is
〈H〉=
CN
∫
dxH(x)e−βH(x)
CN
∫
dx e−βH(x)
=−
1
Q(N,V,T)
∂
∂β
Q(N,V,T)
=−
∂
∂β
lnQ(N,V,T). (4.3.19)
Thus, eqn. (4.3.18) becomes
A+
∂
∂β
lnQ(N,V,β) +β
∂A
∂β
= 0, (4.3.20)
where the fact that
T
∂A
∂T
=T
∂A
∂β
∂β
∂T
=−T
∂A
∂β
1
kT^2
=−β
∂A
∂β
(4.3.21)
has been used. We just need to show that eqn. (4.3.17) is the solution to eqn. (4.3.20),
which is a first-order differential equation forA. Differentiating eqn. (4.3.17) with
respect toβgives
β
∂A
∂β
=
1
β
lnQ(N,V,β)−
∂
∂β
lnQ(N,V,β). (4.3.22)
Substituting eqns. (4.3.17) and (4.3.22) into eqn. (4.3.20) yields
−
1
β
lnQ(N,V,β) +
∂
∂β
lnQ(N,V,β) +
1
β
lnQ(N,V,β)−
∂
∂β
lnQ(N,V,β) = 0,
which verifies thatA=−kTlnQis the solution. Therefore, from eqn. (4.2.6), it is clear
that the macroscopic thermodynamic observables are given in terms of the partition
function by