Phase space and partition function 141The link between the macroscopic thermodynamic properties in eqn.(4.2.6) and
the microscopic states contained inQ(N,V,T) is provided through the relation
A(N,V,T) =−kTlnQ(N,V,T) =−1
βlnQ(N,V,β). (4.3.17)In order to see that eqn. (4.3.17) provides the connection between the thermodynamic
state functionA(N,V,T) and the partition functionQ(N,V,T), we note thatA=
E−TSand thatS=−∂A/∂T, from which we obtain
A=E+T
∂A
∂T
. (4.3.18)
We also recognize thatE =〈H(x)〉, the ensemble average of the Hamiltonian. By
definition, this ensemble average is
〈H〉=
CN
∫
dxH(x)e−βH(x)
CN∫
dx e−βH(x)=−
1
Q(N,V,T)
∂
∂βQ(N,V,T)
=−
∂
∂βlnQ(N,V,T). (4.3.19)Thus, eqn. (4.3.18) becomes
A+
∂
∂βlnQ(N,V,β) +β∂A
∂β= 0, (4.3.20)
where the fact that
T∂A
∂T
=T
∂A
∂β∂β
∂T=−T
∂A
∂β1
kT^2=−β∂A
∂β(4.3.21)
has been used. We just need to show that eqn. (4.3.17) is the solution to eqn. (4.3.20),
which is a first-order differential equation forA. Differentiating eqn. (4.3.17) with
respect toβgives
β∂A
∂β=
1
βlnQ(N,V,β)−∂
∂βlnQ(N,V,β). (4.3.22)Substituting eqns. (4.3.17) and (4.3.22) into eqn. (4.3.20) yields
−
1
βlnQ(N,V,β) +∂
∂βlnQ(N,V,β) +1
βlnQ(N,V,β)−∂
∂βlnQ(N,V,β) = 0,which verifies thatA=−kTlnQis the solution. Therefore, from eqn. (4.2.6), it is clear
that the macroscopic thermodynamic observables are given in terms of the partition
function by