Examples 147
the integration ofxover all space with no significant loss of accuracy. Therefore, the
partition function becomes
Q(β) =
1
h
∫∞
−∞
dpe−βp
(^2) / 2 m
∫∞
−∞
dxe−βmω
(^2) x (^2) / 2
=
1
h
(
2 πm
β
) 1 / 2 (
2 π
mω^2
) 1 / 2
=
2 π
βhω
=
1
β ̄hω
, (4.5.19)
where ̄h=h/ 2 π. From eqn. (4.5.19), it follows that the energy isE=kT, the pressure
isP= 0 (which is expected for a bound system), and the heat capacity isCV=k.
If we now consider a collection ofNuncoupled harmonic oscillators with different
masses and frequencies with a Hamiltonian
H=
∑N
i=1
[
p^2 i
2 mi
+
1
2
miω^2 ix^2 i
]
. (4.5.20)
Since the oscillators are not identical, the 1/N! factor is not needed, and the partition
function is just a product of single particle partition functions for theNoscillators:
Q(N,β) =
∏N
i=1
1
β ̄hωi
. (4.5.21)
For this system, the energy isE=NkT, and the heat capacity is simplyCv=Nk.
4.5.3 The harmonic bead-spring model
Another important class of harmonic models is a simple model of a polymer chain
based on harmonic nearest-neighbor interactions. Consider a polymer with endpoints
at positionsrandr′havingNrepeat units in between, each of which will be treated
as a single ’particle’. The particles are indexed from 0 toN+ 1, and the Hamiltonian
takes the form
H=
N∑+1
i=0
p^2 i
2 m
+
1
2
mω^2
∑N
i=0
(ri−ri+1)^2 , (4.5.22)
wherer 0 ,...,rN+1andp 0 ,...,pN+1are the positions and momenta of the particles
with the additional identificationr 0 =randrN+1=r′andp 0 =pandpN+1=p′as
the positions and momenta of the endpoint particles, andmω^2 is the force constant.
The polymer is placed in a cubic container of volumeV =L^3 such thatLis much
larger than the average distance between neighboring particles|rk−rk+1|.
Let us first consider the case in which the endpoints are fixed at given positionsr
andr′so thatp=p′= 0. We seek to calculate the partition functionQ(N,V,T,r,r′)
given by