26 Classical mechanics
ηi=xi−xi 0 , (1.7.3)
wherexi 0 −x(i+1)0=bi. The Hamiltonian in terms of the new variables and their
conjugate momenta is given by
H=
∑N
i=1
p^2 ηi
2 m
+
1
2
N∑− 1
i=1
mω^2 (ηi−ηi+1)^2. (1.7.4)
The equations of motion obeyed by this simple system can be obtaineddirectly from
Hamilton’s equations and take the form
η ̇i=
pηi
m
p ̇η 1 =−mω^2 (η 1 −η 2 )
p ̇ηi=−mω^2 (2ηi−ηi+1−ηi− 1 ), i= 2,...,N− 1
p ̇ηN=−mω^2 (ηN−ηN− 1 ), (1.7.5)
which can be expressed as second-order equations
̈η 1 =−ω^2 (η 1 −η 2 )
̈ηi=−ω^2 (2ηi−ηi+1−ηi− 1 ), i= 2,...,N− 1
η ̈N=−ω^2 (ηN−ηN− 1 ). (1.7.6)
In eqns. (1.7.5) and (1.7.6), it is understood that theη 0 =ηN+1= 0, since these
have no meaning in our system. Eqns. (1.7.6) must be solved subjectto a set of initial
conditions{η 1 (0),...,ηN(0),η ̇ 1 (0),...,η ̇N(0)}.
The general solution to eqns. (1.7.6) can be written in the form of a Fourier series
ηi(t) =
∑N
k=1
Ckaikeiωkt, (1.7.7)
whereωkis a set of frequencies,aikis a set of expansion coefficients, andCkis a
complex scale factor. Substitution of this ansatz into eqns. (1.7.6)gives
∑N
k=1
Ckωk^2 a 1 keiωkt=ω^2
∑N
k=1
Ckeiωkt(a 1 k−a 2 k)
∑N
k=1
Ckωk^2 aikeiωkt=ω^2
∑N
k=1
Ckeiωkt(2aik−ai+1,k−ai− 1 ,k)
∑N
k=1
Ckωk^2 aNkeiωkt=ω^2
∑N
k=1
Ckeiωkt(aNk−aN− 1 ,k). (1.7.8)
Since eqns. (1.7.8) must be satisfied independently for each function exp(iωkt), we
arrive at an eigenvalue equation of the form: