Numerical evaluation 481
and eigenvectors; 3) From the eigenvectors, construct the orthogonal matrixOijthat
diagonalizes A. The forward and inverse transformations are thengiven by
uk=
1
√
P
∑P
l=1
Oklxl
xk=
√
P
∑P
l=1
OTklul. (12.6.17)
Although the eigenvalues emerge directly from the diagonalization procedure, they can
also be constructed by hand according to
λ 2 k− 1 =λ 2 k− 2 = 2
[
1 −cos
(
2 π(k−1)
P
)]
. (12.6.18)
Note the twofold degeneracy. When evaluated in terms of the normal mode variables,
the harmonic coupling term becomes
∑P
k=1
(xk−xk+1)^2 =
∑P
k=2
λku^2 k. (12.6.19)
As with the staging transformation, the harmonic term is now separable. The trans-
formation also has unit Jacobian. Thus, the transformed partitionfunction is identical
to eqn. (12.6.9) if the massesmkare defined asmk=mλk,m′ 1 =m, andm′k=mk.
With this identification, eqns. (12.6.11), (12.6.12), and (12.6.14) areapplicable to the
normal-mode case exactly as written. The only difference occurs when the chain rule
is used to obtain the forces on the normal mode variables, whence we obtain
1
P
∂U
∂u 1
=
1
P
∑P
l=1
∂U
∂xl
1
P
∂U
∂uk
=
1
√
P
∑P
l=1
∂U
∂xl
OlkT. (12.6.20)
In addition to its utility as a computational scheme, the normal-modeformulation
of the path integral has several other interesting features. First, the variableu 1 can
be shown to be equal to
u 1 =
1
P
∑P
k=1
xk P−→→∞
1
β ̄h
∫βh ̄
0
dτ x(τ). (12.6.21)
That is, the sum on the left becomes the continuous integral on theright whenP→∞.
The variableu 1 is an average over all of the path variables and, therefore, corresponds,
for finiteP, to the center-of-mass of the cyclic polymer. This point is also known as
thepath centroid. Note that the force on this mode is also just the average force