186 Chapter 4 • Limits of Functions
Proof. Let f ( x) = sin ( ~). Consider the sequences { Xn} = { nl7f } and
{yn} = {
1
}. Then both Xn ____, 0 and Yn ____, 0, but
~ + 2mr
f(xn) = sin ( x
1
n) = sin(mr) = 0 ____, 0, while
f (Yn) = sin ( y~) = sin(~ + 2mr) = 1 ____, 1.
Thus, lim f(xn) -I- lim f(Yn)· Therefore, by Corollary 4.1.11, lim f(x)
n--+oo n--+CXJ x--+0
does not exist. D
llx
-1/x
y =sin (1/x)
Figure 4.2
EXERCISE SET 4.1
- For each of the following limit statements lim f ( x) = L, do the following:
X--+XQ
(i) Find a value of b > 0 that will guarantee that whenever x is within
distance b from xo (but -I-xo) f(x) is within distance. 01 from L.
(ii) Find a value of b > 0 that will guarantee that whenever x is within
distance b from Xo (but not -I-xo) f(x) will approximate the limit
accurately to 3 decimal places.
(iii) For arbitrary but unknown E > 0, find a value of b > 0 that will
guarantee that whenever x is within distance b of x 0 (but -I-xo)
f(x) is within distance of E of L.
(iv) Prove the given limit statement using Definition 4.1.1
(a) lim(5x - 11) = 4 (b) lim(3x - 8) = - 5
x-1-3 X--+l
(c) lim x^2 = 9 (d) lim x^3 = 8
x--+3 x --+2
x