96 3. Tensor Products
Now let's give an example where a tensor product sequence fails to be
exact.^22 Though elementary, the proof is somewhat delicate and requires a
few preliminary facts.
A discrete group r is called residually finite if there exist subgroups
r ~ r1 ~ r2 ~ ... such that each ri is a finite-index, normal subgroup of
r and nn r n = { e} (the neutral element of r). The key fact is that if r
is residually finite, then the minimal tensor product of the full group C* -
algebras C* (r) 181 C* (r) has a very special state coming from the left and
right regular representations.
If r is any discrete group, then we can consider the product map
>. x p: C*(r) 0 C*(r) __, JIB(£^2 (r))
induced by the (commuting) left and right regular representations. If we
take some elements x = L:::sEriYss, y = L:::tErf3tt E C*(r) (only finitely
many coefficients nonzero), then a straightforward computation shows that
(>. X p(x 181 y)De, De) = L 1Ysf3s·
sEI'
Note that if r happened to be a finite group, then C*(r) 0C*(r) = C*(r) 181
C* (r) and hence we would have a state on the minimal tensor product
satisfying the formula above.
Lemma 3. 7.9. If I' is residually finite, then there exists a stateμ on C* (r)181
C* (r) such that for finite sums
x =Lass, y = Lf3tt E C*(r)
sEI' tEI'
we have
μ(x 181y)=L1Ysf3s·
sEI'
Proof. Since each r /r n is a finite group, we have a sequence of states μn
on C* (r /r n) 181 C* (r /r n) satisfying the formula above (for r /r n). However
we also have quotient mappings 7rn: C*(r) -t C*(I'/I'n) and hence tensor
product *-homomorphisms
Since the intersection of the r n's is just the neutral element, a straightfor-
ward computation shows that any cluster point of the states μno (7rn 1817rn)
must satisfy the right formula. (Hence there is a unique cluster point of the
μn°(1fn1811fn)'s.) D
(^22) In Chapter 6, when we come to Kirchberg's factorization property, we'll revisit these ideas.