1550075568-C-Algebras_and_Finite-Dimensional_Approximations__Brown_

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98 3. Tensor Products

However, it is evident that J 0 C*(r) belongs to the kernel of,\ Xmin p and
hence this *-homomorphism factors through
C* (r) 0 C* (r) ~ C* (r) 0 C* (r)
JQ9C*(r) >. '
so we get our representation 7r.
To finish off the proof, use The Trick to get a u.c.p. map <P: JIB(£^2 (r)) ____,
L(r) such that <I>(x) = x for all x E C~(r). This is very similar to the proof
of Proposition 3.6.9 (with maximal norms replaced by minimal ones and the
right regular representation regarded as originating from C* (r)), so we leave
~~~~~. D

As promised in the last chapter, we finally prove the existence of nonex-
act C* -algebras. This follows immediately from the previous result together
with Proposition 3. 7.8.
Corollary 3.7.12. If r is a nonamenable residually finite group {e.g., IB'n
or SL(n, Z)), then C*(r) is not exact since the sequence
o -> J 0 C*(r) ____, C*(r) 0 C*(r) ____, CHr) 0 C*(r) ____, o
is not exact.

It follows from this corollary that JIB(C^2 ) is not exact either (since exact-
ness passes to subalgebras).
Exercises
Exercise 3."f.1. Use Lemma 3.7.7 to show that if the sequence
O ____, J 0 C ____, A 0 C ____, A/ J 0 C ____, O
is exact and B c C is a C* -subalgebra, then
0 ____, J 0 B ____, A 0 B ____, A/ J 0 B ____, 0
is also exact.
Exercise 3!l.2 (Uniqueness of the extension in Corollary 3.3.12). Let a
and f3 be C*-norms on A8B, where A is the unitization of A. Prove that if
a= f3 on A 8 B, then a= f3 on A 8 B. In particular if A 8 B has a unique
C*-norm, then so does A0B. Hint: Consider ry = max{a,/3} and use the 5
Lemma^23 on the following diagram:
0 -----+ A0ryB --1 A 0ry B -----+ CCl 0 B -----+ 0

l l l
0 -----+ A !Zia B -----+ A !Zia B -----+ CCl 0 B -----+ 0.

(^23) See Mathworld (mathworld.wolfram.com/FiveLemma.html) if you're not familiar with the
5 Lemma.

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