1550078481-Ordinary_Differential_Equations__Roberts_

(jair2018) #1
54 Ordinary Differential Equations

In exercises 7-12 find all points ( c , d) where solutions to the initial

value problem consisting of the given differential equation and the

initial condition y(c) = d may not exist or may not be unique.

7. y' = x/y^2 8. y' = Vfj/x

9. y' = xy/(1- y)


  1. y' = J(y - 4)/x


10. y' = (xy)I/3

12. y' = -y/x + y^114


In exercises 13-22 state the interval on which the solution to the

linear initial value problem exists and is unique.



  1. y' = 4y - 5; y(l) = 4




  2. y' + 3y = 1; y(-2) = 1




  3. y' = ay + b; y(c) = d where a, b, c, and dare real constants.




  4. y' = x^2 +ex - sinx; y(2) = -1




17.

18.

19.

20.

21.

22.

1
y' = xy+--· y(-5) = 0
1 + x^2 '
y
y' = - + cosx; y(-1) = 0
x
y
y' = - + tanx; y(n") = 0
x
I y ~
Y = -4 - x 2 +vx;

I y ~
y = -4 -x 2 +vx;

y' =(cot x)y + cscx;

y(3) = 4

y(l) = -3


y(n/2) = 1
x2 + n


  1. Verify that Y1(x) = 1 and y2(x) = sin(-
    2


-) are both solut ions on


the interval (-ft, ft) of the init ia l value problem

y' = -xJ17; y(O) = 1.
Does this violate the fundamental existence and uniqueness theorem? Ex-
plain.


  1. Verify that Y1 (x) = 9 - 3x and y 2 (x) = -x^2 /4 are both solutions of
    the initial value problem


y' = (-x+ Jx^2 +4y)/2; y(6) = -9.
Does this violate the fundamental existence and uniqueness theorem? Ex-
plain.

Free download pdf