1550251515-Classical_Complex_Analysis__Gonzalez_

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Functions. Limits and Continuity. Arcs and Curves 139


Notation We write


lim f(z) = oo
z-+oo

or f(z) -too as z -too

Example For f(z) = ez, D = {z: Rez > O}, we have limz-+oo f(z) = oo.
In fact, for any given J( > 0 we have


lf(z)I = lezl =ex > K

whenever x > lnK. Hence it suffices to take M > max (O,lnK), 8 =
1/(1 + M^2 )^112 , and z E N6(oo) n D.
It is worth noting that for f ( z) = ez defined on D 1 = { z: Re z = 0},
i.e., for f(iy) = eiY, there is no limit as z = iy -too, and for f(z) = ez
defined in D2 = {z: Rez < O} we have limz-+oo f(z) = 0.


3.10 Infinitely Small and Infinitely Large Functions


Definition 3.5 If limz-+a f(z) = 0 (a finite or oo) it is said that the

function f(z) is an infinitesimal as z -ta, or that f(z) is infinitely small as


z -ta. Clearly, limz-+a g(z) = L (L finite) iff the function f(z) = g(z) -L


is an infinitesimal as z -t a.


Examples



  1. f ( z) = z^2 is an infinitesimal as z -t 0.

  2. F(z) = (z -2)(z^2 + 1) is an infinitesimal z -t 2.

  3. h(z) = 1/z is an infinitesimal as z -t oo.


Definition 3.6 Two infinitesimals f(z) and g(z) as z -ta are said to be


of the same order if limz-+a f(z)/ g(z) = L, where L /= 0 and L /= oo. More

generally, those two infinitesimals are of the same order as z -t a if there


are two positive constants K 1 and K2 such that K1 < lf(z)/g(z)I < K2.'

If limz-+a f(z)/g(z) = 0 then f(z) is called an infinitesimal of higher

order than g(z) (as z -ta). On the other hand, if limz-+a f(z)/g(z) = oo,


then f(z) is said to be of lower order than g(z) (as z -ta). Obviously, if


f(z) is of higher order than g(z), then g(z) is of lower order than f(z).

If limz-+a f(z)/g(z) = 1, the infinitesimals f(z) and g(z) are said to be


equivalent, and we write f(z) "" g(z) as z -t a.
Examples


  1. The infinitesimals f(z) = 2z^2 and g(z) = z^2 + z^4 as z -t 0 are of the


same order since limz-+O f(z)/g(z) = 2.


  1. The infinitesimals f(z) = z^3 +2z^5 and g(z) = z^3 as z -t 0 are equivalent
    since limz-+O f (z) / g(z) = 1.


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