1550251515-Classical_Complex_Analysis__Gonzalez_

(jair2018) #1
Differentiation

From the formulas for f z and fz in polar form we get


e i..PJ z + e -i'l/Jf z -- f r -- Ur + ZVr.
ir(ei'l/J fz -e-i'l/J fz) = f..p = u..p + iv..p
Also, from
z'(t) = lz'(t)ieiB = ei'l/J(t)[r'(t) + ir(t)1fi'(t)]
it follows that
ei(B-1/J) = r'(t) + ir(t) 1/i'(t)

lz'(t)i lz'(t)i


so that
r'(t)

cos(B-1/i) = iz'(t)i' sin(O -1/i) = r(t) l~:gjl


By using (6.10-15) and (6.10-16) in (6.10-14) we find that

349

(6.10-15)

(6.10-16)

f~(z) = e-iB[(ei'l/J fz + e-i'l/J fz) cos((} -1/i) + i(ei..P fz - e-i'l/J fz) sin(O -1/i)]
which simplifies to
(6.10-17)

6.11 TIIE KASNER CIRCLE

Letting ( = f~(z) in formula (6.10-2), or in (6.10-17), we have

., /' = f z + f ;:e -2i8 ' (6.11-1)
From this equation it is clear that for a fixed point z, the arc described by
( as (} varies in the interval [O, 27r] is an oriented circle described twice in
the negative (clockwise) direction (Fig. 6.6). This circle was introduced by
E. Kasner [65], who called it a clock, but it is usually known as the Kasner
circle (following E. R. Hedrick).


'·plane

)


--


Fig. 6.6
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