1550251515-Classical_Complex_Analysis__Gonzalez_

(jair2018) #1
Sequences, Series, and Special Functions 541

Then the coefficients in every column above form a convergent series,
and if we let

we have

00
aok + alk + · · · + amk + · · · = L amk = bk
m=O

00

F(z) = Lbkzk


k=O
at least for JzJ < R.

Proof By Corollary 8.5 the function F(z) is analytic in Jzl < R, and
00
p(k)(z) = L l$:>(z), JzJ <R
m=O
so that, in particular for z = 0,
00

p(o) = 2:: 1$:>(0)


m=O

Now, by the Cauchy-Taylor expansion theorem, the coefficient of zk in the
expansion of F( z) about the origin is

;, p(k>(o) = ;, f 1$:>(0) = f ;, 1$:>(0) = f amk
m=O m=O m=O
=bk

since amk = l~)(O)/k!.

Example Consider the Lambert series


oo m oo
F(z) = """" L.,; _z_ 1 - zm = """"l L.,; m(z)
m=l m=l
This series is uniformly convergent for JzJ _:::; r < 1. In fact,

so that

(8.4-7)
Free download pdf