1550251515-Classical_Complex_Analysis__Gonzalez_

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Sequences, Series, and Special Functions 553

Theorem 8.12 Let f(z) = u(x, y) + iv(x, y) and suppose that the func-
tions u and v are of class cn+i in some circular neighborhood Nr(z) of the
point z = (x, y). Then for z + 6.z E Nr(z) we have
n 1
f(z + 6.z) = f(z) + L k! (fz6.z + fz6.z)(k) +Rn
k=l


(8.6-1)

where the symbolic power has the usual interpretation, and Rn = R 1 ,n +
iR2,n, Ri,n and R 2 ,n being the remainders in the corresponding Taylor
formulas for u and v (as functions of the real variables x and y). ·


Proof From Taylor formula for real functions of two real variables we have
1 1
u(x + 6.x, y + 6.y) = u(x, y) +du+ I d^2 u + · · · + I dnu + Ri,n (8.6-2)



  1. n.
    1 1
    v(x + 6.x, y + 6.y) = v(x, y) + dv +
    21
    d^2 v + · · · + n! dnv + Rz,n (8.6-3)


where


dnu = (u.,6.x + uy6.y)<n),


and


R - l dn+lu ] R - l dn+lv ]
l,n - (n + 1)! x+9Ax ' Z,n - (n + l)! x+9^1 Ax
y+9Ay y+9^1 Ay

with 0 < e < 1, 0 < O' < 1. From (8.6-2) and (8.6-3) we obtain


J(z+D..z) = J(z)+(du+idv)+ ~(d^2 u+id^2 v)+···+ ~(dnu+idnv)+Rn


  1. n.


Now, from

fz = %[(u., + vy) + i(v., - Uy)]
fz =^1 / 2 [(u., - vy) + i(v., + uy)]
J zz =^1 / 4 [( Uxx + 2vxy - Uyy) + i( Vxx - 2Uxy - Vyy )]
etc.

it can be easily verified that


du+ idv = f z6.z + f -z6.z
d^2 u + id^2 v = f zz6.z^2 + 2fz-z6.z6.z + fz--z6.z^2
= (f z6.z + f-z6.z)<^2 )
and in general, we have
dnu + idnv = (fz6.z + fz6.z)(n)

(8.6-4)
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