1550251515-Classical_Complex_Analysis__Gonzalez_

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Singularities/Residues/ Applications

9.6 CHARACTERIZATION OF SOME SIMPLE

FUNCTIONS BY THE NATURE OF THEIR

SINGULARITIES

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Classes of functions that are analytic in a domain except possibly on a
certain set of singular points are determined by the position and type of
those singularities. In this section we investigate the simplest classes of such
functions. We may begin by asking whether there are analytic functions
with no singularities at all in C*. The answer to this question is contained
in the following theorem.


Theorem 9.6 The functions that are regular at every point of C* are the

constant functions.
Proof Clearly, a constant function in C* is regular everywhere in the ex-

tended complex plane. To prove the converse, let f be any function regular


in C*. Since f is regular at oo, lf(z)I is bounded in some neighborhood of


oo, that is, there exists Ki > 0 and R > 0 such that

IJ(z)I R


In the compact set lzl ::::; R, f is regular, hence continuous, and it follows


that for some K 2 > 0 we have

lf(z)J < K2 for lzl::::; R


Therefore,
Jf(z)I <max( Ki, K2)

for all finite z. By Liouville theorem the only functions that are analytic
and bounded in C are the constant func~ions. T.hus f(z) = c for some
constant c. Since f(z) is supposed to be regular at oo [or g(z) = f(l/z)


regular at OJ we must have f ( oo) = c also. '

Corollary 9.1 A nonconstant analytic function in C must have a singular

point at oo.

Examples



  1. A polynomial P(z) = Z::::~=O akzk with an =fa 0, n ;::: 1, has a pole of
    order n at oo.

  2. The function f(z) = sinz has an essential singularity at. oo.


Theorem 9. 7 The functions that are regular in C and have a pole at oo

are the polynomials of degree n ;::: 1.
Proof Obviously, a polynomial of degree n ;::: 1 has at oo a pole of order
n (see Section 5.16, Example 4). Next, let f be regular in C. Then f(z)
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