1550251515-Classical_Complex_Analysis__Gonzalez_

(jair2018) #1
Singularities/Residues/ Applications 677

which gives an alternative method (often advantageous) for the evaluation
of an integral in terms of the residue of the integrand at infinity.


Example To evaluate Ic+(z^3 + 2)/(z^4 + 1) dz, where c+: z = 2eit, 0 ~
t ~ 271".
The integrand has simple poles at the points ak (k = 1,2,3,4), where
at = -1, i.e., at the zeros of z^4 + 1 = 0 (Fig. 9.7). Since all those poles lie
within C*, we may use either (9.9-1) or (9.9-4) in evaluating the integral.
First method. Applying (9.8-2) we have


z^3 + 2 ai + 2 1 1 1 1 1
Res --= --= - + - - = - - -ak
z=a1o z4 + 1 4ai 4 2 ai 4 2
Hence by (9.9-1),

--dz = 27ri """"' - - -ak


J


za + 2.


4
( 1 1 )
c+ z
4
+l f:i 4 2

= 27ri (1 - % t ak) = 27ri
k=l

since "E!=l ak = 0.

Second method. By using (9.7-4) we have

Hence by (9.9-4),


Fig. 9.7

Res za + 2 == -Res ~ 1 + 2z3 = -1
z=oo z^4 + 1 z=O z 1 + z^4

J


z: +
2

dz= -27ri(-1) = 27ri

z + 1
c+
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