Singularities/Residues/ Applications 729
replace the circle 'Yt of that figure (see Fig. 9.29). Then we have
J
fo(z) dz= 1-S fo(x) dx + J fo(z) dz+ rb-£ fo(x) dx
. a+£ ls
r+ -y~+
+ J fo(z)dz+ l~/o(x)dx+ J fo(z)dz
'Yt 'Ydl
a+e J
+ _
8f 0 (x)dx+ f 0 (z)dz (9.11-65)
'YtAs in case (i), we obtain
J
27rBfo(z) dz= y'=A
r+lim e->0 J fo(z) dz= e->0 lim J fo(z) dz= 0
'Yt 'Ytand
yr+R xFig. 9.29