322 Clustering
Prove that for everyk >1 the k-diam clustering function defined in the
previous exercise is not a center-based clustering function.
Hint: Given a clustering input (X,d), with|X|>2, consider the effect of
adding many close-by points to some (but not all) of the members ofX, on
either the k-diam clustering or any given center-based clustering.
- Recall that we discussed three clustering “properties”: Scale Invariance, Rich-
ness, and Consistency. Consider the Single Linkage clustering algorithm.- Find which of the three properties is satisfied by Single Linkage with the
Fixed Number of Clusters (any fixed nonzero number) stopping rule. - Find which of the three properties is satisfied by Single Linkage with the
Distance Upper Bound (any fixed nonzero upper bound) stopping rule. - Show that for any pair of these properties there exists a stopping criterion
for Single Linkage clustering, under which these two axioms are satisfied.
- Find which of the three properties is satisfied by Single Linkage with the
- Given some numberk, letk-Richness be the following requirement:
For any finiteXand every partitionC= (C 1 ,...Ck)ofX(into nonempty subsets)
there exists some dissimilarity functiondoverXsuch thatF(X,d) =C.
Prove that, for every numberk, there exists a clustering function that
satisfies the three properties: Scale Invariance,k-Richness, and Consistency.