1.7. Continuous Random Variables 57F(x)x
110.5(0, 0)Figure 1.7.3:Graph of the cdf of Example 1.7.7.Example 1.7.8.Reinsurance companies are concerned with large losses because
they might agree, for illustration, to cover losses due to wind damages that are
between $2,000,000 and $10,000,000. Say thatXequals the size of a wind loss in
millions of dollars, and suppose it has the cdfFX(x)={
0 −∞<x< 0
1 −(
10
10+x) 3
0 ≤x<∞.If losses beyond $10,000,000 are reported only as 10, then the cdf of this censored
distribution isFY(y)=⎧
⎪⎨⎪⎩0 −∞<y< 0
1 −(
10
10+y) 3
0 ≤y< 10 ,
110 ≤y<∞,
which has a jump of [10/(10 + 10)]^3 =^18 aty= 10.EXERCISES
1.7.1.Let a point be selected from the sample spaceC={c:0<c< 10 }.Let
C⊂Cand let the probability set function beP(C)=∫
C1
10 dz. Define the random
variableXto beX(c)=c^2. Find the cdf and the pdf ofX.
1.7.2.Let the space of the random variableX beC={x:0<x< 10 }and
letPX(C 1 )=^38 ,whereC 1 ={x:1<x< 5 }. Show thatPX(C 2 )≤^58 ,where
C 2 ={x:5≤x< 10 }.
1.7.3.Let the subsetsC 1 ={^14 <x<^12 }andC 2 ={^12 ≤x< 1 }of the space
C ={x:0<x< 1 }of the random variableXbe such thatPX(C 1 )=^18 and
PX(C 2 )=^12 .FindPX(C 1 ∪C 2 ),PX(C 1 c), andPX(C 1 c∩C 2 c).