1.22. MANIPULATING SPECIFIC BIT(S)
ANDis executed:
Figure 1.103:OllyDbg:i= 4, is there that bit in the input value? Yes. (ZF=0)ZFis 0 because this bit is present in the input value.
Indeed,0x12345678 & 0x10 = 0x10.
This bit counts: the jump is not triggering and the bit counterincrementing.
The function returns 13. This is total number of bits set in0x12345678.
GCC
Let’s compile it in GCC 4.4.1:
Listing 1.289: GCC 4.4.1
public f
f proc near
rt = dword ptr -0Ch
i = dword ptr -8
arg_0 = dword ptr 8
push ebp
mov ebp, esp
push ebx
sub esp, 10h
mov [ebp+rt], 0
mov [ebp+i], 0
jmp short loc_80483EF
loc_80483D0:
mov eax, [ebp+i]
mov edx, 1
mov ebx, edx
mov ecx, eax
shl ebx, cl
mov eax, ebx
and eax, [ebp+arg_0]
test eax, eax
jz short loc_80483EB
add [ebp+rt], 1
loc_80483EB:
add [ebp+i], 1
loc_80483EF: