Assembly Language for Beginners

1.29. SIMD

sz = dword ptr 4
ar1 = dword ptr 8
ar2 = dword ptr 0Ch
ar3 = dword ptr 10h

push edi

push esi

push ebx

push esi

mov edx, [esp+10h+sz]

test edx, edx

jle loc_15B

mov eax, [esp+10h+ar3]

cmp edx, 6

jle loc_143

cmp eax, [esp+10h+ar2]

jbe short loc_36

mov esi, [esp+10h+ar2]

sub esi, eax

lea ecx, ds:0[edx*4]

neg esi

cmp ecx, esi

jbe short loc_55

loc_36: ; CODE XREF: f(int,int ,int ,int )+21
cmp eax, [esp+10h+ar2]
jnb loc_143
mov esi, [esp+10h+ar2]
sub esi, eax
lea ecx, ds:0[edx4]
cmp esi, ecx
jb loc_143

loc_55: ; CODE XREF: f(int,int ,int ,int *)+34
cmp eax, [esp+10h+ar1]
jbe short loc_67
mov esi, [esp+10h+ar1]
sub esi, eax
neg esi
cmp ecx, esi
jbe short loc_7F

loc_67: ; CODE XREF: f(int,int ,int ,int *)+59
cmp eax, [esp+10h+ar1]
jnb loc_143
mov esi, [esp+10h+ar1]
sub esi, eax
cmp esi, ecx
jb loc_143

loc_7F: ; CODE XREF: f(int,int ,int ,int *)+65
mov edi, eax ; edi = ar3
and edi, 0Fh ; is ar3 16-byte aligned?
jz short loc_9A ; yes
test edi, 3
jnz loc_162
neg edi
add edi, 10h
shr edi, 2

loc_9A: ; CODE XREF: f(int,int ,int ,int *)+84
lea ecx, [edi+4]
cmp edx, ecx
jl loc_162
mov ecx, edx
sub ecx, edi
and ecx, 3
neg ecx
add ecx, edx
test edi, edi