Mathematics Times – July 2019

(Ben Green) #1
in the n-gon. An n-gon will have exterior angles

of

360
n

(the sum of all the exterior angles must

add up to 360 degrees). Consider the pentagon
and hexagon:

Therefore, the interior angles of the hexagon
are 120 degrees each. In an edge to edge tiling,
at a point where the corners of hexagons meet,
we would require the interior angles to sum to
360 degrees. This happens if we have 3
hexagons, and we see that our regular tiling
indeed has three hexagons meeting at each
corner next line.
The interior angles of the pentagon are 108
degrees each. At a point where the corners of
pentagons meet, we would require the interior
angles to sum to 360 degrees. Three pentagons
would be 324 degrees, which is not enough,
and four pentagons would be 432 degrees,
which is too much. This is why we cannot tile
the plane with pentagons.

This also explains why we have four squares
meeting at each corner for squares
(4 90 360)  , and six triangles meeting at
each corner for triangles (6 60 360) .
The only edge to edge regular tilings are the
ones with equilateral triangles, squares, or
hexagons.
5.Sol: We can solve this problem in two methods,
one is using graph and the other is using
algebra.


Graphical Method

From the graph, we can observe there are
four intersecting points, that is four points
satisfying the simultaneous equations.
algebraic Method Given simultaneous
equations are rewritten as
x y ^212
x y^2   12
Which yields x y x y^2   ^2. That is

x y x y^2   ^2. After simplifying, we get
x y  0 and x y  1
Now
x = y: Implies that x x^2   12
i.e., x x^2   12 0
Solving the above equation we get x=-4,3.
Therefore corresponding y coordinates are -
4, 3 respectively.

Thus two intersecting are ( 4, 4)  and (3,3).
x + y = 1: That isy  1 x. Substituting in
any of the equation and solving for

5.Sol:


Graphical Method

1 1 44
2

x

 
. we can get two

corresponding values y by substituting x
values. Hence it has two intersecting points.
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