2019-03-01_Physics_Times

Let V 0 and T 0 are the volume of the gas and

temperature initially in each part. After displacing

the adiabatic separator the new volumes are V 1

and V 2 and temperatures are T 1 and T 2

Given that

1

2

7

3

V

V



V V V 1   2 20

0 0

1 2

14 6

&

10 10

V V

 V V 

1

1 0

0 0 1

14

10

V

T V T



    

 

 





(i)

1

(^10)
0 0 2
6
10
V
T V T

   
 
 


(ii)
From (i) & (ii) we get
1
2
3
7
T
T

Number of fissions per second
Power output
Energy released per fission

6
17
6 19
3.2 10
1 10
200 10 1.6 10

  
  
 Number of fission per minute
    60 1 10^17 6 10^18
5
6
0.5
5 10
10
V V
E m
d 
   
The value of Rs should be such that the current
through the zener diode is much larger than the
load current as five times the load current i.e.,
Iz20 mA. The total current through Rs is
therefore, 24 mA. The voltage drop across Rs is
10 6 4 V.  This gives
s 3
4 V
R 167
24 10 A
  

Note Slight variation in the value of the resistor
does not matter, what is important is that the current
Iz should be sufficiently larger than IL.
(^) rad (1 )
I
P
c
  where
 coefficient of reflection
(1 )
I
F A
C
  
6
8
200
(1 0.6) 1.07 10
3 10
F A N
A
      
 
  0.6 100 60%
Wavelength  increases in the sequence
VIBGYOR. Refractve index  decreases as
wavelength increases. Therefore,  decreases in
the sequence VIBGYOR.
As
C sin^11 ,

  
 
 
therefore, critical angle C
increases in the sequence VIBGYOR. For green
colour,  i C.
For yellow, orange and red, critical angle is greater.
Therefore, i is less than critical angle for YOR.
These colours will not suffer total internal
reflection. They will emerge from glass-air interface.
No light is emitted from the second polaroid,
so P and P 1 2 are perpendicular to each other
Let the initial intensity of light is I 0. So Intensity
of light after transmission from first polaroid is^0
2
I
.
Intensity of light emitted from P 3 is 1 0 2
2
I
I  cos
Intensity of light transmitted from last polaroid i.e.,
from 2 1 2  (^90) ^022
2
I
P I cos   cos .sin 
 
0 2 0 2
2 2
8 8
I I
 sin cos   sin 
As, asin n 
19.Sol:
20.Sol:
21.Sol:
22.Sol:
23.Sol:
24.Sol:
25.Sol:
26.Sol: ay 3
D
 
or
0.3 10^3 5 10^3
( )
3 3 1
ay
D F
D

   
  

 5 10 m 5000 A^7  