(E) e − 1(A) ln 2
(B) e
(C) 1 + e
(D) −ln 2
(E)- If we let x = tan θ, then is equivalent to
(A)
(B)
(C)
(D)
(E)- If the substitution is used, then is equivalent to
(A)
(B)
(C)
(D)
(E)- The table above shows some values of continuous function f and its first derivative. Evaluate
xf (x)f ′(x)
0 11 3
2 15 2
4 16 −1
6 12 −3
8 7 0