It can be shown that (a > 0) converges if p < 1 but diverges if p 1. Figure N7–25 shows aninterpretation of in terms of areas where 1, and 3. Only the first-quadrant area under
to the left of x = 1 exists.
Note that
BC ONLYFIGURE N7–25
EXAMPLE 26EXAMPLE 27
This integral diverges.EXAMPLE 28BC ONLYEXAMPLE 29