- (A) Since f ′(1) = 0 and f ′ changes from negative to positive there, f reaches a minimum at x =
- Although f ′(2) = 0 as well, f ′ does not change sign there, and thus f has neither a
maximum nor a minimum at x = 2.
- Although f ′(2) = 0 as well, f ′ does not change sign there, and thus f has neither a
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