- (D) Let y = (x^3 − 4x^2 + 8)ecos(x^2 ). The equation of the tangent at point (2, y (2)) is y − y(2) = y
′(2)(x − 2). Note that y(2) = 0. To find the y-intercept, let x = 0 and solve for y: y = −2y ′(2).
A calculator yields y = 4.161.
dmanu
(dmanu)
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