BUKU ANALISIS KOMPLEKS LANJUTAN

(Jenriani Astutiyk9Clq) #1

2 푧

3

+푧

2

+ 4


2

(푧+ 2 푖)(푧− 2 푖)

푑푧

퐶 1

=− 2 휋푖×푔

1

(푧

0

)=− 2 휋푖(푔

1

(푧

0

))

=− 2 휋푖×

2 (− 2 푖

3

)+(− 2 푖

2

)+ 4

(− 2 푖

2

)((− 2 푖)− 2 푖)

=− 2 휋푖×

2 ( 8 푖)+(− 4 )+ 4

(− 4 푖)(− 4 푖)

=− 2 휋푖

16 푖

16 푖

=− 2 휋푖

Kemudian pada kurva 퐶

2

dengan 푧

0

= 0 :


2 푧

3

+푧

2

+ 4


2

(푧+ 2 푖)(푧− 2 푖)

푑푧

퐶 2

,푧

0

= 0 (orde 2) ; 푔

2

(푧)=

2 푧

3

+푧

2

+ 4

(푧

2

+ 4 )

Maka hasil integralnya (searah jarum jam):


2 푧

3

+푧

2

+ 4


2

(푧+ 2 푖)(푧− 2 푖)

푑푧

퐶 2

=

− 2 휋푖

( 2 − 1 )!

×푔

2

(
2 − 1

)

(푧

0

)=− 2 휋푖(푔

2

(푧

0

))

=− 2 휋푖[

( 6 푧

2

+ 2 푧)

(


2

+ 4

)

−( 2 푧)( 2 푧

3

+푧

2

+ 4 )

(푧

2

+ 4 )

2

]

=− 2 휋푖[

( 6 ( 0

2

)+ 2 ( 0 ))( 0

2

+ 4 )−( 2 ( 0 ))( 2 ( 0

3

)+ 0

2

+ 4 )

( 0

2

+ 4 )

2

]

=− 2 휋푖[

( 0 )( 4 )−( 0 )( 4 )

( 4

2

)

]= 0

Berikutnya pada kurva 퐶

3

dengan 푧

0

= 2 푖 :


2 푧

3

+푧

2

+ 4


2

(푧+ 2 푖)(푧− 2 푖)

푑푧

퐶 3

,푧

0

= 2 푖 (orde 1) ; 푔

3

(


)

=

2 푧

3

+푧

2

+ 4


2

(푧+ 2 푖)

Maka hasil integralnya (searah jarum jam):


2 푧

3

+푧

2

+ 4


2

(푧+ 2 푖)(푧− 2 푖)

푑푧

퐶 3

=− 2 휋푖×푔

3

(푧

0

)=− 2 휋푖(푔

3

(푧

0

))

=− 2 휋푖[

2 ( 2 푖

3

)+( 2 푖

2

)+ 4

( 2 푖

2

)( 2 푖+ 2 푖)

]

=− 2 휋푖[

2 (− 8 푖)+(− 4 )+ 4

(− 4 )( 4 푖)

]=− 2 휋푖

− 16 푖

− 16 푖

=− 2 휋푖

Maka :


2 푧

3

+푧

2

+ 4


2

(푧+ 2 푖)(푧− 2 푖)

푑푧


=− 2 휋푖+ 0 − 2 휋푖=− 4 휋푖

Latihan Soal

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