QMGreensite_merged

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64 CHAPTER5. DYNAMICSOFTHEQUANTUMSTATE


ThenrewritingtheSchrodingerequation(anditscomplexconjugate)as


∂ψ
∂t

=


i ̄h
2 m

∂^2 ψ
∂x^2


i
̄h


∂ψ∗
∂t

= −


i ̄h
2 m

∂^2 ψ∗
∂x^2

+


i
h ̄

Vψ∗ (5.12)

andinsertinginto(5.11),wehave

<p> = m


dx

{(

i ̄h
2 m

∂^2 ψ∗
∂x^2

+


i
̄h

Vψ∗

)

+ ψ∗x

(
i ̄h
2 m

∂^2 ψ
∂x^2


i
h ̄


)}

= m

(
i ̄h
2 m

)∫
dx{−(

∂^2


∂x^2

ψ∗)xψ+ψ∗x

∂^2


∂x^2

ψ}

=



dxψ∗

(
−i ̄h


∂x

)
ψ (5.13)

whichisthesameruleforcomputing

asinthepreviousV = 0 case.Then


∂t<p> = −i ̄h


dx

[
∂ψ∗
∂t

∂ψ
∂x

+ψ∗

∂^2 ψ
∂t∂x

]

= −i ̄h


dx

[
∂ψ∗
∂t

∂ψ
∂x


∂ψ∗
∂x

∂ψ
∂t

]

= −i ̄h


dx

{(

i ̄h
2 m

∂^2 ψ∗
∂x^2

+


i
̄h


)
∂ψ
∂x


∂ψ∗
∂x

(
i ̄h
2 m

∂^2 ψ
∂x^2


i
̄h


)}

= −


h ̄^2
2 m


dx

[
∂^2 ψ∗
∂x^2

∂ψ
∂x

+


∂ψ∗
∂x

∂^2 ψ
∂x^2

]

+



dx

[
ψ∗V

∂ψ
∂x

+


∂ψ∗
∂x


]
(5.14)

Againapplyingintegrationbypartstothe firsttermofthefirst integral, andthe
secondtermofthesecondintegral,wefind


∂t<p> = −

̄h^2
2 m


dx

[

∂ψ∗
∂x

∂^2 ψ
∂x^2

+


∂ψ∗
∂x

∂^2 ψ
∂x^2

]

+



dx

[
ψ∗V

∂ψ
∂x

−ψ∗


∂x

(Vψ)

]

=



dx

[
ψ∗V

∂ψ
∂x

−ψ∗V

∂ψ
∂x

−ψ∗

∂V


∂x

ψ

]
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