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8.4. THEFINITESQUAREWELL:BOUNDSTATES 133


EvenParityBoundStates


Therequirementthatφ(x)=φ(−x)alsoimpliesthatA=B. Sowehavealto-
gether


φI(x) = Ae−


2 mEx/ ̄h

φII(x) = CEcos

[√
2 m(V 0 −E)x/ ̄h

]

φIII(x) = Ae

√ 2 mEx/ ̄h
(8.55)

Thecontinuityofthewavefunctionatx=±arequires


Ae−


2 mEa/ ̄h=C
Ecos

[√
2 m(V 0 −E)a/ ̄h

]
(8.56)

whilethecontinuityofthefirstderivativeatx=±agives



2 mEAe−


2 mEa/ ̄h=


2 m(V 0 −E)CEsin

[√
2 m(V 0 −E)a/ ̄h

]
(8.57)

Dividingequation(8.57)byequation(8.56)resultsinatranscendentalequation
forE=−E

E=



V 0 −Etan

[√
2 m(V 0 −E)a/ ̄h

]
(8.58)

whichdeterminestheenergyeigenvalues.
Thistranscendentalequationcanbesolvedgraphically,byplottingtheleftand
righthandsidesoftheequationtofindthepointsatwhichthetwocurvesintersect.
TheresultisshowninFig.[8.15].Welearnfromthefigurethatthesolutions,denoted
byEn,withnanoddinteger,areallatE<V 0. ThisisbecauseforE>V 0 thetangent
ineq. (8.58)becomesahyperbolictangent,sotherhsdiverges to−∞asx→∞,
neveragainintersecting



E. EachsolutionEnislocatedbetweenpointswherethe
tangentequals0;these”nodes”occurat


E=V 0 −(kπ)^2

̄h^2
2 ma^2

(k= 0 , 1 , 2 ,...) (8.59)

andsinceE>0,thismeansthatthenumberKofeven-parityenergyeigenvaluesis
thelargestnumbersuchthat


[(K−1)π]^2

̄h^2
2 ma^2

≤V 0 (8.60)


Thusthereareafinitenumber-andnolessthanone!-ofeven-parityboundstates.
ThenumberKofsuchboundstatesincreasesasthewellbecomesdeeper(largerV 0 ),
andwider(largera).


OddParityBoundStates

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