QMGreensite_merged

(bbancia) #1

134 CHAPTER8. RECTANGULARPOTENTIALS


Thistime, the requirement that φ(−x) = −φ(x)implies that B = −A, and
CE=0. Thewavefunctionhastheform


φI(x) = Ae−


2 mEx/ ̄h

φII(x) = COsin

[√
2 m(V 0 −E)x/ ̄h

]

φIII(x) = −Ae


2 mEx/ ̄h (8.61)

Fromcontinuityofthewavefunctionatx=±awehave


Ae−


2 mEa/ ̄h=COsin

[√
2 m(V 0 −E)a/ ̄h

]
(8.62)

andfromcontinuityofthefirstderivativeatx=±a




2 mEAe−


2 mEa/ ̄h=


2 m(V 0 −E)COcos

[√
2 m(V 0 −E)a/ ̄h

]
(8.63)

Dividingeq. (8.63)byeq. (8.62)givesusthetranscendentalequationfortheenergies
ofoddparityboundstates



E = −


V 0 −Ectn

[√
2 m(V 0 −E)a/ ̄h

]

=



V 0 −Etan

[√
2 m(V 0 −E)

a
h ̄

+


π
2

]
(8.64)

whichcanbesolvedgraphically, asshowninFig. [8.16]. Onceagain,thereareas
manyrootsastherearenodesofthetangent;thistimethenodesarelocatedat


E=V 0 −[(k+

1


2


)π]^2

̄h^2
2 ma^2

(k= 0 , 1 , 2 ,...) (8.65)

andthenumberofoddparitynodesisthelargestintegerMsuchthat


[(K−


1


2


)π]^2

̄h^2
2 ma^2

<V 0 (8.66)


Notethatfor


V 0 <

(
π
2

) 2
̄h^2
2 ma^2

(8.67)


therearenoodd-parityboundstates.


Tosumup,wehavefoundthatforafinitesquarewell


  1. Thenumberofboundstateenergiesisfinite,andthereisatleastoneboundstate;

  2. Thenumberofboundstatesincreaseswiththewidthanddepthofthewell;

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