134 CHAPTER8. RECTANGULARPOTENTIALS
Thistime, the requirement that φ(−x) = −φ(x)implies that B = −A, and
CE=0. Thewavefunctionhastheform
φI(x) = Ae−
√
2 mEx/ ̄h
φII(x) = COsin
[√
2 m(V 0 −E)x/ ̄h
]
φIII(x) = −Ae
√
2 mEx/ ̄h (8.61)
Fromcontinuityofthewavefunctionatx=±awehave
Ae−
√
2 mEa/ ̄h=COsin
[√
2 m(V 0 −E)a/ ̄h
]
(8.62)
andfromcontinuityofthefirstderivativeatx=±a
−
√
2 mEAe−
√
2 mEa/ ̄h=
√
2 m(V 0 −E)COcos
[√
2 m(V 0 −E)a/ ̄h
]
(8.63)
Dividingeq. (8.63)byeq. (8.62)givesusthetranscendentalequationfortheenergies
ofoddparityboundstates
√
E = −
√
V 0 −Ectn
[√
2 m(V 0 −E)a/ ̄h
]
=
√
V 0 −Etan
[√
2 m(V 0 −E)
a
h ̄
+
π
2
]
(8.64)
whichcanbesolvedgraphically, asshowninFig. [8.16]. Onceagain,thereareas
manyrootsastherearenodesofthetangent;thistimethenodesarelocatedat
E=V 0 −[(k+
1
2
)π]^2
̄h^2
2 ma^2
(k= 0 , 1 , 2 ,...) (8.65)
andthenumberofoddparitynodesisthelargestintegerMsuchthat
[(K−
1
2
)π]^2
̄h^2
2 ma^2
<V 0 (8.66)
Notethatfor
V 0 <
(
π
2
) 2
̄h^2
2 ma^2
(8.67)
therearenoodd-parityboundstates.
Tosumup,wehavefoundthatforafinitesquarewell
- Thenumberofboundstateenergiesisfinite,andthereisatleastoneboundstate;
- Thenumberofboundstatesincreaseswiththewidthanddepthofthewell;