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194 CHAPTER12. THEHYDROGENATOM


whichreduces,asshowninthepreviouslecture,tothe”radialequation”forRkl(r)


d^2 Rkl
dr^2

+


2


r

dRkl
dr

+


[
2 m
̄h^2

{Ekl+

e^2
r

}−


l(l+1)
r^2

]
Rkl(r)= 0 (12.5)

or [
1
r


d^2
dr^2

r−

l(l+1)
r^2

+


2 me^2
̄h^2

1


r

+


2 mE
̄h^2

]
R(r)= 0 (12.6)

Weareinterestedinthespectrumofatomichydrogen,sothismeanswewould
liketosolvefortheboundstates, i.e. thosestatesforwhichE<0. Fromnowon,
wetakeE=−|E|<0.Multiplytheaboveequationbyrontheleft,anddefine


u(r)=rR(r) (12.7)

sothat [
d^2
dr^2



l(l+1)
r^2

+


2 me^2
̄h^2

1


r


2 m|E|
̄h^2

]
u(r)= 0 (12.8)

Thisequationinvolvestwoconstants,namely


2 mE
̄h^2

and

2 me^2
̄h^2

(12.9)


whichwecanreducetooneconstantbyrescalingr. Define


k^2 =

2 m|E|
̄h^2

and r=

ρ
2 k

(12.10)


Substituteinto(12.8),andwefind


d^2 u
dρ^2


l(l+1)
ρ^2

u+

(
λ
ρ


1


4


)
u= 0 (12.11)

wherewehavedefined


λ=

me^2
k ̄h^2

=


1


ka 0

(12.12)


(a 0 isthe Bohrradius ̄h^2 /me^2 ). Theproblemisreduced to finding values λand
functionsu(ρ)whichsatisfy(12.11).
Thestrategyforsolving(12.11)istofirstsolvetheequationintheasymptotic
limitsρ→∞andρ→0.Withthesolutionsforverylargeandverysmallρinhand,
wethenlookforasolutionwhichinterpolatesbetweenthesetworegions.
Beginwithρ→∞. Thentermsproportionalto 1 /ρ^2 and 1 /ρcanbedropped,
andtheequationbecomes
d^2 u
dρ^2



u
4

= 0 (12.13)

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