382 CHAPTER25. AGLIMPSEOFQUANTUMFIELDTHEORY
Asintheordinaryharmonic-oscillatorproblem,wesolveHΨ=EΨbyintroducing
raising-loweringoperators
ak =
√
mωk
2 ̄h
[
Qk+
i
mωk
Pk
]
a†k =
√
mωk
2 ̄h
[
Q−k−
i
mωk
P−k
]
Qk =
√
̄h
mωk
(ak+a†−k)
Pk =
1
2 i
√
2 ̄hmωk(ak−a†−k) (25.18)
where
ωk=
√
σk
m
(25.19)
Intermsoftheseoperators,onefindsthat
H=
∑
k
̄hωk(a†kak+
1
2
) (25.20)
where
[ak,a†k′]=δk,k′ (25.21)
Theproblemhasbeenreducedtosolvingthedynamicsofasetofuncoupledharmonic
oscillators; oneoscillatorfor eachwavenumberk intherange −^12 (N−1) ≤ k ≤
1
2 (N−1).
Allloweringoperatorsannihilatetheharmonic-oscillatorgroundstate,sowere-
quirethat,forallwavenumbersk
akΨ 0 [Q]= 0 (25.22)
or
̄h
∂
∂Q−k
Ψ 0 =−mωkQkψ 0 (25.23)
Thisequationcanbesolvedbyinspection,andwehave,forthegroundstateofthe
solid,
Ψ 0 = Nexp
[
−
m
̄h
∑
k
ωkQkQ−k
]
= Nexp
[
−
√
m
̄h
∑
k
{ 2 K(1−cos(
2 πk
N
)}^1 /^2 QkQ∗k
]
(25.24)
withground-state(or”zero-point”)energy
E 0 =
∑
k
1
2
̄hωk (25.25)