Solutions 155
The horizontally flying bullet hitting the body
will not change the vertical component of the mo-
mentum of the formed system, and hence the ver-
tical component of the velocity of the body-bullet
system will be
m m to
m+M u— m+111 g -1/.2 •The time t 2 required for the body-bullet sys-
tem to traverse the remaining half the distance
can be determined from the equation
h , gt1— --= uto-
2 2This gives
t
to
_
1/m 2 + (m+M) 2 — m
1/.2 m+MThus, the total time of fall of the body to the
ground (M > m) will bet. t° ilm2+(m+1/1)2+31 Alto -tr2.
ir2 m+M1.53. In order to solve the problem, we shall use
the momentum conservation law for the system.
We choose the coordinate system as shown in
Fig. 159: the x-axis is directed along the velocity
vi of the body of mass ml, and the y-axis is directedalong the velocity v 2 of the body of mass m (^2).
After the collision, the bodies will stick together
and fly at a velocity u. Therefore,
rnivi =--- (m 1 + m 2 ) ux, m 2 v 2 = (m (^1) + m 2 ) uy•
The kinetic energy of the system before the collision
was
u =