Solutions(^161)
1.58. At the moment of snapping of the right
string, the rod is acted upon by the tension T of
Fig. 164
the left string and the forces N 1 and N 2 of normal
pressure of the loads of mass m 1 and m2 (Fig. 165).
Since the rod is weightless (its mass is zero), the
Fig. 165
equations of its translatory and rotary motions will
have the form
—T ± N 1 — N2 = 0, N11 = 2N21.
11 0771