166 Aptitude Test Problems in Physics
and by the energy conservation law
4mvt,my! 2 -4_^ 4mq,
2 ' 2 '
where v 1 and v 2 are the velocities of the proton and
the a-particle in the stationary reference frame
after the collision, and in and 4m are the masses
of the proton and the a-particle respectively.
Let us consider the collision of these particles
in the centre-of-mass system, i.e. in an inertial
reference frame moving relative to the stationary
reference frame at a velocity
4mvo 4
+
v' vo
4m 5
(the numerator of the first fraction contains the
total momentum of the system, and the denomina-
tor contains its total mass). Figure 168 shows the
oo
O
'2
2/
Al-- —
U~Svo
Fig. 168
velocity vo and the velocities of the a-particle
(vector OB) and the proton (vector OA) in the cen-
tre-of-mass system before the collision: OB
(1/5)vo and OA = (4/5)vo. According to the mo-
mentum conservation law, after the collision, the
velocity vectors OB and OA of the a-particle and
the proton must lie on the same straight line, and
the relation OB':OA' = 1:4 (see Fig. 168) must
be satisfied. According to the energy conservation
law, OB' = OB and OA' OA (prove this!).