Solutions (^173)
Then
t.= Ati+ At 2 +. AtN
1 (A/) 2
2 (A/) 2 N (Al) 2 (Al) 2 N (N+1)
VT yr VT 2 •
Since N is large, we have
(A/) 2 N 2 12
t —
2vr 2vr '
/= V2vrt.
Fig. 173
1.72. During the time T, the distance covered by
the blue ball is co (u T = 2n/TIT3 (Fig. 174),
where co = 2n/ T is the rotational frequency. Dur-
ing the same time, the centre of mass of the green
b
27r1/
-)
i3 T
ur
and the white ball will be displaced by a distance
co (1/2 T The rod connecting the green