182 Aptitude Test Problems in Physics
the velocity v of the station immediately after
the collision through the relation
VR
2 =v2x/i•
(4)
Solving Eqs. (1)-(4) together and considering that
vf = ii-GM/R, we determine the velocity of the
meteorite before the collision:
. 17 58GM
u=
R •
1.83. For a body of mass m resting on the equator
of a planet of radius R, which rotates at an angu-
lar velocity w, the equation of motion has the
form
mco 2 R = mg' — N,
where N is the normal reaction of the planet sur-
face, and g' = 0.0Ig is the free-fall acceleration on
the planet. By hypothesis, the bodies on the equa-
tor are weightless, i.e. N = 0. Considering that
w = 2n/T, where T is the period of rotation of
the planet about its axis (equal to the solar day),
we obtain
,
R= 111 3 g -
Substituting the values T = 8.6 X 10' a and
g' 0.1 m/s 3 , we get
1.8 X 10 7 m = 18 000 km.
1.84. We shall write the equation of motion for
Neptune and the Earth around the Sun (for the
sake of simplicity, we assume that the orbits are
circular):
GMmN
mNwNRN = R2
G
MARE
MME
RI •