Copyright © Swun Math Grade 8 Unit 2 Lesson 7 P TE
Student Practice
Unit 2 · Lesson 7: Zero and Negative Exponents
Directions: Simplify the expression. Write the solution using a positive exponent.
47 ⋅ 4 −^2
48
Solution:
4 7+(−2)
48
45
48 = 4
5−8 (Students might want to write 5 – 8)
4 −3=
1
43
2푏푏^4
푏푏^5
Solution:
2 푏푏^4
푏푏^5
= 2푏푏4−5
2 푏푏−1 make the exponent positive so 푏푏−1=^1 푏푏
2
푏푏
1
푚푚^4
⋅
1
푚푚−4
Solution:
1
푚푚4+(−4)
1
푚푚^0
=
1
1
= 1
- 6 −^5 ⋅ 6 −^5
Solution:
6 −10= 6110
- 푝푝−^3 ⋅푝푝^3
Solution:
푝푝−3+3
푝푝^0 = 1
7 푛푛−^9
푛푛−5
Solution:
7 푛푛−9
푛푛−5
= 7푛푛−9−(−5)
7 푛푛−4 make exponent positive so 푛푛−4which is (^) 푛푛^14
7 푛푛−4=
7
푛푛^4
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