Grade 8 Unit 1 Lesson 7 P TE
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Input/Model
(Teacher Presents)
Directions: Estimate the decimal value. Use a calculator to check.
- −√ 75
Solution:
- −√ 75 can be thought of as (- 1) • −√ 75
- −√ 75 can be approximated in the same manner and multiplied by –1
- When considering√ 75 on a number line, the perfect square less than 75 is 64
• (^) √ 64 = 8
- The perfect square greater than 75 is 81.
• (^) √ 81 = 9
• Now make the statement (^) √ 64 < √ 75 < √ 81.
- Simplify 8 <√ 75 < 9
- Recall, −√ 75 = (–1) •√ 75. Therefore, −√ 75 is between –8 and –9.
- Calculator: −√ 75 ≈−8.7
- √
150
2
Solution:
- First, focus on √ 150
- On a number line, the perfect square less than 150 is 144.
• (^) √ 144 = 12
- The perfect square greater than 150 is 169.
• (^) √ 169 = 13
- Now, make the statement √ 144 < √ 150 <√ 169.
- Simplify 12 <√ 150 < 13
- So, √ 150 is between 12 and 13.
- Looking at the original ratio, √^1502 I can now make the statement that, √^1502 is between^122 and^132 or 6 <
√ 150 < 6.5
- Calculator: √^1502 ≈6.1