292 COMPUTATIONAL COMPLEXITY
~~ bee-dance ‘2
‘~ bee-dance
111000
r
(p,xxooxx ;O)
Figure 6.4: The ten moves.
Because limn+W t(n)/n = 00, we have that, for sufficiently large n,
n+lk + 10 l t(n)
m
- 16 < c l t(n).
m -
- 16 < c l t(n).
Thus, A E DTIME(c l t(n)).^0
To get a better understanding of Theorems 6.9 and 6.10, we study some
examples in the following.
Example 6.11 Suppose lim,,, tl(n)/n = 00. If tl(n) = tz(n) for st@-
ciently large n, then DTIME(tl(n)) = DTIME(tz(n)).
Proof. Suppose t 1 (n) = tz(n) for n > no. Then, for n > no, max{n+l, tl(n)}
= max{n+ 1, ta(n)}. Al so, for 1 < 12 < no, there exists a constant c > 1 such
that max{n + 1, tl(n)} 5 c l max(n +?, tz(n)}. Thus, for any n > - 1,
max{n + l,tl(n)} < - c l max{n + 1, ta(n)}.